Two resistors 4 Ω and 6 Ω are connected in parallel to 24 V. Total current?

• A. 4 A
• B. 6 A
• C. 10 A
• D. 14 A

Answer: (C)

When resistors are in parallel, the same voltage appears across each branch and the total current is the sum of the branch currents. The 4 Ω branch draws 24/4 = 6 A, and the 6 Ω branch draws 24/6 = 4 A. Adding these gives 6 + 4 = 10 A.

Another way is to find the equivalent resistance for the parallel combination: 1/R_eq = 1/4 + 1/6 = 5/12, so R_eq = 12/5 = 2.4 Ω. Then I = 24 / 2.4 = 10 A. So the total current is 10 A.