A force does 12 J of work on a 2 kg object starting from rest. What is the final velocity?

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Multiple Choice

A force does 12 J of work on a 2 kg object starting from rest. What is the final velocity?

Explanation:
Work done on an object changes its kinetic energy. Since it starts from rest, all the work goes into motion: W = ΔK = (1/2) m v^2. So v = sqrt(2W/m). Plugging in W = 12 J and m = 2 kg gives v = sqrt(2×12 ÷ 2) = sqrt(12) ≈ 3.46 m/s. Therefore the final velocity is about 3.46 m/s.

Work done on an object changes its kinetic energy. Since it starts from rest, all the work goes into motion: W = ΔK = (1/2) m v^2. So v = sqrt(2W/m). Plugging in W = 12 J and m = 2 kg gives v = sqrt(2×12 ÷ 2) = sqrt(12) ≈ 3.46 m/s. Therefore the final velocity is about 3.46 m/s.

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